What is the extreme f(x,y)=x^2y+3xy^2 ?

The extreme f(x,y)=x^2y+3xy^2 is None

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extreme f(x,y)=x^2y+3xy^2

extreme points

f (x, y) = x^{2} y + 3 x y^{2}

None

Solution steps

Find the critical points:

None

x^{2} y + 3 x y^{2}

has no critical points, therefore there are no extreme points

None

f (x) = x^{4} + y^{4} - 4 x y + 1

f (x) = \frac{3 x - 6}{x + 2}

f (x, y) = 1 - x^{2} + 2 y^{2}

f (x, y) = 60 x - 2 x^{2} - 3 y^{2} + 30 y

\frac{x ^{2}}{x - 4}