What is the extreme f(x)=8x+9x^{8/9} ?

The extreme f(x)=8x+9x^{8/9} is Minimum(-1,1),Maximum(0,0)

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extreme f(x)=8x+9x^{8/9}

extreme points

f (x) = 8 x + 9 x^{\frac{8}{9}}

Minimum (- 1, 1), Maximum (0, 0)

Solution steps

f^{'} (x) = 8 + \frac{8}{x ^{\frac{1}{9}}}

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

8 x + 9 x^{\frac{8}{9}} : 1

Minimum (- 1, 1)

Plug

x = 0

into

8 x + 9 x^{\frac{8}{9}} : 0

Maximum (0, 0)

Minimum (- 1, 1), Maximum (0, 0)

f (x, y) = 3 x^{2} - 2 x y + y^{2} - 8 y

f (x) = - 5 x + 3 ln (4 x)

f (x, y) = x y + 4 x

g (t) = 3 [u (t - 6) - u (t - 7)]

f (x) = \frac{3 x}{x ^{2} + 1}

What is the extreme f(x)=8x+9x^{8/9} ?
The extreme f(x)=8x+9x^{8/9} is Minimum(-1,1),Maximum(0,0)