What is the extreme f(x)=((x-4)^2)/(x+10) ?

The extreme f(x)=((x-4)^2)/(x+10) is Maximum(-24,-56),Minimum(4,0)

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extreme f(x)=((x-4)^2)/(x+10)

extreme points

f (x) = \frac{( x - 4 ) ^{2}}{x + 10}

Maximum (- 24, - 56), Minimum (4, 0)

Solution steps

f^{'} (x) = \frac{x ^{2} + 20 x - 96}{( x + 10 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 24,

Decreasing

: - 24 < x < - 10,

Decreasing

: - 10 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 24

into

\frac{( x - 4 ) ^{2}}{x + 10} : - 56

Maximum (- 24, - 56)

Plug

x = 4

into

\frac{( x - 4 ) ^{2}}{x + 10} : 0

Minimum (4, 0)

Maximum (- 24, - 56), Minimum (4, 0)

f (x) = 4 x - 1

- 2 x^{3} + 3 x^{2} - 12 x

f (x) = 2 y^{2} + x^{2} - x^{2} y

f (x) = \frac{x}{x ^{2} + 100}

f (x) = \frac{4}{3} x^{3} + 4 x^{2} - 252 x + 7

What is the extreme f(x)=((x-4)^2)/(x+10) ?
The extreme f(x)=((x-4)^2)/(x+10) is Maximum(-24,-56),Minimum(4,0)