What is the extreme f(x)=((x-4)^2)/(x+10) ?

The extreme f(x)=((x-4)^2)/(x+10) is Maximum(-24,-56),Minimum(4,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=((x-4)^2)/(x+10)

extreme

Maximum (- 24, - 56), Minimum (4, 0)

Solution steps

f^{'} (x) = \frac{x ^{2} + 20 x - 96}{( x + 10 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 24,

Decreasing

: - 24 < x < - 10,

Decreasing

: - 10 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 24

into

\frac{( x - 4 ) ^{2}}{x + 10} : - 56

Maximum (- 24, - 56)

Plug

x = 4

into

\frac{( x - 4 ) ^{2}}{x + 10} : 0

Minimum (4, 0)

Maximum (- 24, - 56), Minimum (4, 0)

What is the extreme f(x)=((x-4)^2)/(x+10) ?
The extreme f(x)=((x-4)^2)/(x+10) is Maximum(-24,-56),Minimum(4,0)