en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme y=3x^2-12x+13

Solution

extreme points

y = 3 x^{2} - 12 x + 13

Solution

Minimum (2, 1)

Solution steps

f^{'} (x) = 6 x - 12

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

3 x^{2} - 12 x + 13 : 1

Minimum (2, 1)

Graph

Popular Examples

extreme f(x)= 1/4 x^4-2x^3+3 extreme points

f (x) = \frac{1}{4} x^{4} - 2 x^{3} + 3

extreme f(x)=((-8x^3+3x^2))/4 extreme points

f (x) = \frac{( - 8 x ^{3} + 3 x ^{2} )}{4}

extreme f(x)=2x^3+x^2-4x+4 extreme points

f (x) = 2 x^{3} + x^{2} - 4 x + 4

extreme f(x)=(5+x)^5 extreme points

f (x) = (5 + x)^{5}

extreme f(x,y)=y(e^x-1)extreme points

f (x, y) = y (e^{x} - 1)

Frequently Asked Questions (FAQ)

What is the extreme y=3x^2-12x+13 ?
The extreme y=3x^2-12x+13 is Minimum(2,1)