What is the extreme f(x)=x^3-12x^2+45x+5 ?

The extreme f(x)=x^3-12x^2+45x+5 is Maximum(3,59),Minimum(5,55)

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extreme f(x)=x^3-12x^2+45x+5

extreme points

f (x) = x^{3} - 12 x^{2} + 45 x + 5

Maximum (3, 59), Minimum (5, 55)

Solution steps

f^{'} (x) = 3 x^{2} - 24 x + 45

Find intervals:

Increasing

: - \infty < x < 3,

Decreasing

: 3 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = 3

into

x^{3} - 12 x^{2} + 45 x + 5 : 59

Maximum (3, 59)

Plug

x = 5

into

x^{3} - 12 x^{2} + 45 x + 5 : 55

Minimum (5, 55)

Maximum (3, 59), Minimum (5, 55)

f (x, y) = 2 - x^{4} + 2 x^{2} - y^{2}

f (x) = - x^{\frac{5}{3}} + 5 3 x

f (x) = 2 x^{3} - 15 x^{2} - 300 x + 2

F (t) = e^{a t}

f (x) = e^{- a x}

What is the extreme f(x)=x^3-12x^2+45x+5 ?
The extreme f(x)=x^3-12x^2+45x+5 is Maximum(3,59),Minimum(5,55)