What is the extreme f(x,y)= 414/23 x^{2/3}y^{1/3} ?

The extreme f(x,y)= 414/23 x^{2/3}y^{1/3} is None

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extreme f(x,y)= 414/23 x^{2/3}y^{1/3}

extreme points

f (x, y) = \frac{414}{23} x^{\frac{2}{3}} y^{\frac{1}{3}}

None

Solution steps

Find the critical points:

None

\frac{414}{23} x^{\frac{2}{3}} y^{\frac{1}{3}}

has no critical points, therefore there are no extreme points

None

f (x) = 5 x - 4 ln (4 x)

f (x) = x^{4} - 3 x^{2} = x^{2} (x^{2} - 3)

g (x, y) = x^{3} + y^{3} - 3 x - 3 y

f (x) = - x^{6} - 3 x^{3} + x + 1

x^{2} = - 4 a y

What is the extreme f(x,y)= 414/23 x^{2/3}y^{1/3} ?
The extreme f(x,y)= 414/23 x^{2/3}y^{1/3} is None