What is the extreme f(x)=(x^2-14x+49)/(x-10) ?

The extreme f(x)=(x^2-14x+49)/(x-10) is Maximum(7,0),Minimum(13,12)

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extreme f(x)=(x^2-14x+49)/(x-10)

extreme points

f (x) = \frac{x ^{2} - 14 x + 49}{x - 10}

Maximum (7, 0), Minimum (13, 12)

Solution steps

f^{'} (x) = \frac{x ^{2} - 20 x + 91}{( x - 10 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 7,

Decreasing

: 7 < x < 10,

Decreasing

: 10 < x < 13,

Increasing

: 13 < x < \infty

Plug

x = 7

into

\frac{x ^{2} - 14 x + 49}{x - 10} : 0

Maximum (7, 0)

Plug

x = 13

into

\frac{x ^{2} - 14 x + 49}{x - 10} : 12

Minimum (13, 12)

Maximum (7, 0), Minimum (13, 12)

f (x) = e^{x^{3} - 12 x}

(x - 8 x^{2})^{\frac{1}{3}}

f (x) = x 4 - x^{2}, - 2 \leq x \leq 2

x^{2} + 8 x + 18

f (x) = x e^{- \frac{x}{2}}

What is the extreme f(x)=(x^2-14x+49)/(x-10) ?
The extreme f(x)=(x^2-14x+49)/(x-10) is Maximum(7,0),Minimum(13,12)