What is the extreme f(x)=-x^3+3x^2+9x-3 ?

The extreme f(x)=-x^3+3x^2+9x-3 is Minimum(-1,-8),Maximum(3,24)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=-x^3+3x^2+9x-3

extreme points

f (x) = - x^{3} + 3 x^{2} + 9 x - 3

Minimum (- 1, - 8), Maximum (3, 24)

Solution steps

f^{'} (x) = - 3 x^{2} + 6 x + 9

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 3,

Decreasing

: 3 < x < \infty

Plug

x = - 1

into

- x^{3} + 3 x^{2} + 9 x - 3 : - 8

Minimum (- 1, - 8)

Plug

x = 3

into

- x^{3} + 3 x^{2} + 9 x - 3 : 24

Maximum (3, 24)

Minimum (- 1, - 8), Maximum (3, 24)

\frac{x}{x ^{2} + 16}

f (x) = - 4 cos (3 x) - 4

f (x, y) = 200 y^{2} + x^{2} - x^{2} y

2 x^{4} - 16 x^{2} + 3

F (Y, Z) = Y + Y Z

What is the extreme f(x)=-x^3+3x^2+9x-3 ?
The extreme f(x)=-x^3+3x^2+9x-3 is Minimum(-1,-8),Maximum(3,24)