What is the extreme f(x)=-x^2+10,-3<= x<= 4 ?

The extreme f(x)=-x^2+10,-3<= x<= 4 is Minimum(-3,1),Maximum(0,10),Minimum(4,-6)

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extreme f(x)=-x^2+10,-3<= x<= 4

extreme points

f (x) = - x^{2} + 10, - 3 \leq x \leq 4

Minimum (- 3, 1), Maximum (0, 10), Minimum (4, - 6)

Solution steps

Find the critical points:

x = - 3, x = 0, x = 4

Domain of

- x^{2} + 10, - 3 \leq x \leq 4 : - 3 \leq x \leq 4

Find intervals:

Increasing

: - 3 < x < 0,

Decreasing

: 0 < x < 4

Plug the extreme point

x = - 3

into

- x^{2} + 10 \Rightarrow y = 1

Minimum (- 3, 1)

Plug the extreme point

x = 0

into

- x^{2} + 10 \Rightarrow y = 10

Maximum (0, 10)

Plug the extreme point

x = 4

into

- x^{2} + 10 \Rightarrow y = - 6

Minimum (4, - 6)

Minimum (- 3, 1), Maximum (0, 10), Minimum (4, - 6)

f (x, y) = - x^{2} - y^{2} + x + 2 y - 1

\frac{2}{x + 5}

f (x) = - 3 x^{3} - \frac{63}{2} x^{2} - 90 x + 1

f (x) = 3 + x + x^{2}

f (x, y) = 6 x y - x^{3} - 3 y^{2}

What is the extreme f(x)=-x^2+10,-3<= x<= 4 ?
The extreme f(x)=-x^2+10,-3<= x<= 4 is Minimum(-3,1),Maximum(0,10),Minimum(4,-6)