What is the extreme f(x,y)=-x^2-y^2+x+2y-1 ?

The extreme f(x,y)=-x^2-y^2+x+2y-1 is Maximum(1/2 ,1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x,y)=-x^2-y^2+x+2y-1

extreme points

f (x, y) = - x^{2} - y^{2} + x + 2 y - 1

Maximum (\frac{1}{2}, 1)

Solution steps

Find the critical points:

(\frac{1}{2}, 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = 4

Check the sign of at each critical point

Check critical point

(\frac{1}{2}, 1) :

Maximum

Maximum (\frac{1}{2}, 1)

\frac{2}{x + 5}

f (x) = - 3 x^{3} - \frac{63}{2} x^{2} - 90 x + 1

f (x) = 3 + x + x^{2}

f (x, y) = 6 x y - x^{3} - 3 y^{2}

f (x) = \frac{x + 4}{x ^{2} - 3 x - 28}

What is the extreme f(x,y)=-x^2-y^2+x+2y-1 ?
The extreme f(x,y)=-x^2-y^2+x+2y-1 is Maximum(1/2 ,1)