What is the extreme f(x,y)=113x+15y-x^2-2y^2+3xy ?

The extreme f(x,y)=113x+15y-x^2-2y^2+3xy is Saddle(-497,-369)

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extreme f(x,y)=113x+15y-x^2-2y^2+3xy

extreme points

f (x, y) = 113 x + 15 y - x^{2} - 2 y^{2} + 3 x y

Saddle (- 497, - 369)

Solution steps

Find the critical points:

(- 497, - 369)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 4

D (x, y) = - 1

Check the sign of at each critical point

Check critical point

(- 497, - 369) :

Saddle

Saddle (- 497, - 369)

f (x) = - x^{3} + 6 x^{2} + 15 x + 4

\frac{csc ( x )}{1 + csc ( x )}

f (x) = x^{\frac{8}{3}}, - 8 \leq x \leq 1

f (x) = - 2 sin^{2} (x), \frac{π}{4} \leq x \leq 2 π

f (x) = e^{x} - 2 x

What is the extreme f(x,y)=113x+15y-x^2-2y^2+3xy ?
The extreme f(x,y)=113x+15y-x^2-2y^2+3xy is Saddle(-497,-369)