What is the inverse of f(x)=7x^2+2 ?

The inverse of f(x)=7x^2+2 is sqrt((x-2)/7),-sqrt((x-2)/7)

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inverse of f(x)=7x^2+2

inverse

f (x) = 7 x^{2} + 2

\frac{x - 2}{7}, - \frac{x - 2}{7}

Solution steps

y = 7 x^{2} + 2

Replace

x

with

y

x = 7 y^{2} + 2

Solve for

y, x = 7 y^{2} + 2

\frac{x - 2}{7}, - \frac{x - 2}{7}

f (x) = \frac{4}{x - 5} + 3

\frac{5}{x - 4}

f (x) = \frac{1}{x + 3} + 4

y = \frac{7}{x}

f (x) = 7 - \frac{1}{2} x, x > 2

What is the inverse of f(x)=7x^2+2 ?
The inverse of f(x)=7x^2+2 is sqrt((x-2)/7),-sqrt((x-2)/7)