What is the extreme f(x)=(x^2-10x+25)/(x-10) ?

The extreme f(x)=(x^2-10x+25)/(x-10) is Maximum(5,0),Minimum(15,20)

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extreme f(x)=(x^2-10x+25)/(x-10)

extreme points

f (x) = \frac{x ^{2} - 10 x + 25}{x - 10}

Maximum (5, 0), Minimum (15, 20)

Solution steps

f^{'} (x) = \frac{x ^{2} - 20 x + 75}{( x - 10 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 5,

Decreasing

: 5 < x < 10,

Decreasing

: 10 < x < 15,

Increasing

: 15 < x < \infty

Plug

x = 5

into

\frac{x ^{2} - 10 x + 25}{x - 10} : 0

Maximum (5, 0)

Plug

x = 15

into

\frac{x ^{2} - 10 x + 25}{x - 10} : 20

Minimum (15, 20)

Maximum (5, 0), Minimum (15, 20)

f (x, y) = 3 x^{2} + x y - y^{2}

f (x) = \frac{x ^{5}}{20} - 4 x^{3}

x^{3} + 9 x^{2}

f (x) = x^{3} + y^{3} - 27 x y

- \frac{6}{x - 7}

What is the extreme f(x)=(x^2-10x+25)/(x-10) ?
The extreme f(x)=(x^2-10x+25)/(x-10) is Maximum(5,0),Minimum(15,20)