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Popular >

extreme f(x)=ln(x^2-1)

Solution

extreme points

f (x) = ln (x^{2} - 1)

Solution

None

Solution steps

f^{'} (x) = \frac{2 x}{x ^{2} - 1}

Find intervals:

None

None

Graph

Popular Examples

extreme y^3+x^3-21/2 y^2-3x+30y extreme points

y^{3} + x^{3} - \frac{21}{2} y^{2} - 3 x + 30 y

extreme f(x)=e^{8x}+e^{-x}extreme points

f (x) = e^{8 x} + e^{- x}

extreme f(x)=-2x^2+4x extreme points

f (x) = - 2 x^{2} + 4 x

extreme g(x)=x^3-3x^2+1 extreme points

g (x) = x^{3} - 3 x^{2} + 1

extreme f(x)=((x-1)^2)/x extreme points

f (x) = \frac{( x - 1 ) ^{2}}{x}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=ln(x^2-1) ?
The extreme f(x)=ln(x^2-1) is None