What is the extreme f(x,y)=4x-8xy+2y+1 ?

The extreme f(x,y)=4x-8xy+2y+1 is Saddle(1/4 , 1/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x,y)=4x-8xy+2y+1

extreme points

f (x, y) = 4 x - 8 x y + 2 y + 1

Saddle (\frac{1}{4}, \frac{1}{2})

Solution steps

Find the critical points:

(\frac{1}{4}, \frac{1}{2})

\frac{\partial ^{2} f}{\partial x ^{2}} = 0

D (x, y) = - 64

Check the sign of at each critical point

Check critical point

(\frac{1}{4}, \frac{1}{2}) :

Saddle

Saddle (\frac{1}{4}, \frac{1}{2})

+ 5^{x} - 4

f (x) = x^{3} - x^{2} - x + 6

x 6 - x

f (x) = x e^{\frac{2}{x}}

f (x) = - \frac{x ^{3}}{3} - 2 x^{2} + 5 x - 2

What is the extreme f(x,y)=4x-8xy+2y+1 ?
The extreme f(x,y)=4x-8xy+2y+1 is Saddle(1/4 , 1/2)