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Popular >

extreme f(x)=x^2+9x-5

Solution

extreme points

f (x) = x^{2} + 9 x - 5

Solution

Minimum (- \frac{9}{2}, - \frac{101}{4})

Solution steps

f^{'} (x) = 2 x + 9

Find intervals:

Decreasing

: - \infty < x < - \frac{9}{2},

Increasing

: - \frac{9}{2} < x < \infty

Plug

x = - \frac{9}{2}

into

x^{2} + 9 x - 5 : - \frac{101}{4}

Minimum (- \frac{9}{2}, - \frac{101}{4})

Graph

Popular Examples

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f (x) = \frac{ln ( x )}{x}, 1 \leq x \leq 3

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f (x) = \frac{x}{( x ^{2} + 9 )}

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+9x-5 ?
The extreme f(x)=x^2+9x-5 is Minimum(-9/2 ,-101/4)