What is the extreme f(x)=-x^3+3x+4 ?

The extreme f(x)=-x^3+3x+4 is Minimum(-1,2),Maximum(1,6)

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extreme f(x)=-x^3+3x+4

extreme points

f (x) = - x^{3} + 3 x + 4

Minimum (- 1, 2), Maximum (1, 6)

Solution steps

f^{'} (x) = - 3 x^{2} + 3

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = - 1

into

- x^{3} + 3 x + 4 : 2

Minimum (- 1, 2)

Plug

x = 1

into

- x^{3} + 3 x + 4 : 6

Maximum (1, 6)

Minimum (- 1, 2), Maximum (1, 6)

f (x) = \frac{x ^{2} - 8}{x + 3}

f (x, y) = 3 x y + 2 x y^{2}

\frac{1}{3} (x - 2.1)^{2} + 7.9

f (x, y) = 120 x + 120 y - x y - x^{2} - y^{2}

f (x) = (x + 7)^{\frac{2}{3}}

What is the extreme f(x)=-x^3+3x+4 ?
The extreme f(x)=-x^3+3x+4 is Minimum(-1,2),Maximum(1,6)