What is the extreme f(x)=x^3-3x-3 ?

The extreme f(x)=x^3-3x-3 is Maximum(-1,-1),Minimum(1,-5)

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extreme f(x)=x^3-3x-3

extreme points

f (x) = x^{3} - 3 x - 3

Maximum (- 1, - 1), Minimum (1, - 5)

Solution steps

f^{'} (x) = 3 x^{2} - 3

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

x^{3} - 3 x - 3 : - 1

Maximum (- 1, - 1)

Plug

x = 1

into

x^{3} - 3 x - 3 : - 5

Minimum (1, - 5)

Maximum (- 1, - 1), Minimum (1, - 5)

x^{2} + y^{2} - x y

f (x) = 14 x^{2} - 2 x^{3} + 4 x y

f (x) = ln (x^{2} + 7 x + 15)

f (x) = - \frac{2}{x ^{2}}

x^{3} - 3 x^{2} + 5

What is the extreme f(x)=x^3-3x-3 ?
The extreme f(x)=x^3-3x-3 is Maximum(-1,-1),Minimum(1,-5)