What is the extreme f(x,y)=xsqrt(1+y^3) ?

The extreme f(x,y)=xsqrt(1+y^3) is None

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extreme f(x,y)=xsqrt(1+y^3)

extreme points

f (x, y) = x 1 + y^{3}

None

Solution steps

Find the critical points:

None

x 1 + y^{3}

has no critical points, therefore there are no extreme points

None

f (x) = \frac{1 + x}{1 + x ^{2}}

f (x) = x^{2} y + 2 x y - y^{2} - 3 y

f (x) = x^{3} - 3 x + 2, (- 2, 2)

f (x) = 288 y^{2} + x^{2} - x^{2} y

f (x, y) = 5 x^{2} - x y + 3 y^{2}

What is the extreme f(x,y)=xsqrt(1+y^3) ?
The extreme f(x,y)=xsqrt(1+y^3) is None