What is the extreme f(x)=x^3+3x^2-9x-1 ?

The extreme f(x)=x^3+3x^2-9x-1 is Maximum(-3,26),Minimum(1,-6)

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extreme f(x)=x^3+3x^2-9x-1

extreme points

f (x) = x^{3} + 3 x^{2} - 9 x - 1

Maximum (- 3, 26), Minimum (1, - 6)

Solution steps

f^{'} (x) = 3 x^{2} + 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 3

into

x^{3} + 3 x^{2} - 9 x - 1 : 26

Maximum (- 3, 26)

Plug

x = 1

into

x^{3} + 3 x^{2} - 9 x - 1 : - 6

Minimum (1, - 6)

Maximum (- 3, 26), Minimum (1, - 6)

f (x, y) = (\frac{1}{2} - x^{2} + y^{2}) e^{1 - x^{2} - y^{2}}

f (x) = x^{2} - 8 x + 9

f (x, y) = x^{3} - y^{3} + 6 x y

f (x, y) = 288 y^{2} + x^{2} - x^{2} y

f (x, y) = x (x - 4) y (y - 4)

What is the extreme f(x)=x^3+3x^2-9x-1 ?
The extreme f(x)=x^3+3x^2-9x-1 is Maximum(-3,26),Minimum(1,-6)