What is the extreme f(x)=2x^3-3x^2-12x-3 ?

The extreme f(x)=2x^3-3x^2-12x-3 is Maximum(-1,4),Minimum(2,-23)

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extreme f(x)=2x^3-3x^2-12x-3

extreme points

f (x) = 2 x^{3} - 3 x^{2} - 12 x - 3

Maximum (- 1, 4), Minimum (2, - 23)

Solution steps

f^{'} (x) = 6 x^{2} - 6 x - 12

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 1

into

2 x^{3} - 3 x^{2} - 12 x - 3 : 4

Maximum (- 1, 4)

Plug

x = 2

into

2 x^{3} - 3 x^{2} - 12 x - 3 : - 23

Minimum (2, - 23)

Maximum (- 1, 4), Minimum (2, - 23)

f (x) = 5 (5 x)^{x}, 0.05 \leq x \leq 1

f (x) = 3 x^{3} e^{- x}, - 1 \leq x \leq 6

y = x^{4} - 4 x^{2} = x^{2} (x^{2} - 4)

f (x) = 2 x^{3} + 3 x^{2} - 12 x + 7

- x + 2 cos (x)

What is the extreme f(x)=2x^3-3x^2-12x-3 ?
The extreme f(x)=2x^3-3x^2-12x-3 is Maximum(-1,4),Minimum(2,-23)