What is the extreme f(x,y,z)=x^2+y^2 ?

The extreme f(x,y,z)=x^2+y^2 is Minimum(0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x,y,z)=x^2+y^2

extreme points

f (x, y, z) = x^{2} + y^{2}

Minimum (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = 4

Check the sign of at each critical point

Check critical point

(0, 0) :

Minimum

Minimum (0, 0)

f (x) = x^{11} - 3 x^{10} + 2

f (x, y) = y^{2} ln (x y)

f (x) = 5 sin^{2} (x), 0 \leq x \leq π

f (x, y) = x^{3} + y^{3} - 3 x^{2} - 9 y^{2} - 9 x

f (x, y) = \frac{1}{3} 36 - 9 x^{2} - 4 y^{2}

What is the extreme f(x,y,z)=x^2+y^2 ?
The extreme f(x,y,z)=x^2+y^2 is Minimum(0,0)