What is the extreme f(x)= 1/2 x+2,-3<= x<= 3 ?

The extreme f(x)= 1/2 x+2,-3<= x<= 3 is Minimum(-3, 1/2),Maximum(3, 7/2)

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extreme f(x)= 1/2 x+2,-3<= x<= 3

extreme points

f (x) = \frac{1}{2} x + 2, - 3 \leq x \leq 3

Minimum (- 3, \frac{1}{2}), Maximum (3, \frac{7}{2})

Solution steps

Find the critical points:

x = - 3, x = 3

Domain of

\frac{1}{2} x + 2, - 3 \leq x \leq 3 : - 3 \leq x \leq 3

Find intervals:

Increasing

: - 3 < x < 3

Plug the extreme point

x = - 3

into

\frac{1}{2} x + 2 \Rightarrow y = \frac{1}{2}

Minimum (- 3, \frac{1}{2})

Plug the extreme point

x = 3

into

\frac{1}{2} x + 2 \Rightarrow y = \frac{7}{2}

Maximum (3, \frac{7}{2})

Minimum (- 3, \frac{1}{2}), Maximum (3, \frac{7}{2})

f (x) = \frac{x ^{2}}{x ^{2} + 27}

f (x) = 2 x^{2} + 4 x + 10

f (x) = 1 - x^{3} - 3 x - 2 x^{2} + 3 x^{4}

f (x) = (x - 1) (x + 2) (x + 4)

f (x) = 4 x^{5} - 3 x^{3} - 3 x + 1

What is the extreme f(x)= 1/2 x+2,-3<= x<= 3 ?
The extreme f(x)= 1/2 x+2,-3<= x<= 3 is Minimum(-3, 1/2),Maximum(3, 7/2)