What is the extreme w(x,y)=6+(3xy)/(75) ?

The extreme w(x,y)=6+(3xy)/(75) is Saddle(0,0)

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extreme w(x,y)=6+(3xy)/(75)

extreme points

w (x, y) = 6 + \frac{3 x y}{75}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = 0

D (x, y) = - \frac{1}{625}

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

f (x) = 14 x y - x^{3} - 7 y^{2}

x^{\frac{4}{3}} (7 x^{2} + 10 x - 210)

f (x) = - x^{3} + 3 x^{2} - 8

f (x) = 8 x^{2} - 2 x^{4}

P (q, s) = q + 2 + s

What is the extreme w(x,y)=6+(3xy)/(75) ?
The extreme w(x,y)=6+(3xy)/(75) is Saddle(0,0)