What is the extreme f(p,q)=pq-1/p-1/q ?

The extreme f(p,q)=pq-1/p-1/q is Minimum(-1,-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(p,q)=pq-1/p-1/q

extreme points

f (p, q) = pq - \frac{1}{p} - \frac{1}{q}

Minimum (- 1, - 1)

Solution steps

Find the critical points:

(- 1, - 1)

\frac{\partial ^{2} f}{\partial p ^{2}} = - \frac{2}{q ^{3}}

D (p, q) = \frac{4}{p ^{3} q ^{3}} - 1

Check the sign of at each critical point

Check critical point

(- 1, - 1) :

Minimum

Minimum (- 1, - 1)

3 x^{4} - 4 x^{3} - 36 x^{2} + 5

f (x) = x 18 - x

f (x, y) = x^{2} y + 2 x y - y^{2} - 3 y

f (x) = 5 sin (2 x) + 3

f (x, y) = e^{(x - y)} (x^{2} - 2 y^{2})

What is the extreme f(p,q)=pq-1/p-1/q ?
The extreme f(p,q)=pq-1/p-1/q is Minimum(-1,-1)