en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=sqrt(x+3)+6

Solution

extreme points

f (x) = x + 3 + 6

Solution

Minimum (- 3, 6)

Solution steps

f^{'} (x) = \frac{1}{2 x + 3}

Find intervals:

Increasing

: - 3 < x < \infty

Plug

x = - 3

into

x + 3 + 6 : 6

Minimum (- 3, 6)

Graph

Popular Examples

extreme f(x)=2x^2-8x+5 extreme points

f (x) = 2 x^{2} - 8 x + 5

extreme f(x)=x^4(x-1)^2 extreme points

f (x) = x^{4} (x - 1)^{2}

extreme (4x^2-3x^4)/(2x)extreme points

\frac{4 x ^{2} - 3 x ^{4}}{2 x}

extreme f(x)=2x^3+3x^2-36x-54 extreme points

f (x) = 2 x^{3} + 3 x^{2} - 36 x - 54

extreme f(x)=(2e^{3x})/(-3x-1)extreme points

f (x) = \frac{2 e ^{3 x}}{- 3 x - 1}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=sqrt(x+3)+6 ?
The extreme f(x)=sqrt(x+3)+6 is Minimum(-3,6)