What is the extreme f(x)=x^2+y^2+x^2y+4 ?

The extreme f(x)=x^2+y^2+x^2y+4 is Minimum(0,0),Saddle(sqrt(2),-1),Saddle(-sqrt(2),-1)

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extreme f(x)=x^2+y^2+x^2y+4

extreme points

f (x) = x^{2} + y^{2} + x^{2} y + 4

Minimum (0, 0), Saddle (2, - 1), Saddle (- 2, - 1)

Solution steps

Find the critical points:

(0, 0), (2, - 1), (- 2, - 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = 2 (2 y + 2) - 4 x^{2}

Check the sign of at each critical point

Check critical point

(0, 0) :

Minimum

Check critical point

(2, - 1) :

Saddle

Check critical point

(- 2, - 1) :

Saddle

Minimum (0, 0), Saddle (2, - 1), Saddle (- 2, - 1)

f (x) = \frac{1}{3} x^{3} + 5 x^{2} + 24 x + 7

f (x) = \frac{x ^{2} - 16 x + 64}{x - 10}

f (x, y) = x^{2} + y^{2} - 6 x + 3 y

f (x) = x^{3} + y^{3} - 33 x y

f (x) = x^{3} - 2 x^{2} - 15 x + 3

What is the extreme f(x)=x^2+y^2+x^2y+4 ?
The extreme f(x)=x^2+y^2+x^2y+4 is Minimum(0,0),Saddle(sqrt(2),-1),Saddle(-sqrt(2),-1)