What is the extreme f(x)=10+x^3-(9x^2)/2 ?

The extreme f(x)=10+x^3-(9x^2)/2 is Maximum(0,10),Minimum(3,-7/2)

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extreme f(x)=10+x^3-(9x^2)/2

extreme points

f (x) = 10 + x^{3} - \frac{9 x ^{2}}{2}

Maximum (0, 10), Minimum (3, - \frac{7}{2})

Solution steps

f^{'} (x) = 3 x^{2} - 9 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 0

into

10 + x^{3} - \frac{9 x ^{2}}{2} : 10

Maximum (0, 10)

Plug

x = 3

into

10 + x^{3} - \frac{9 x ^{2}}{2} : - \frac{7}{2}

Minimum (3, - \frac{7}{2})

Maximum (0, 10), Minimum (3, - \frac{7}{2})

f (x) = 5 x + 10 sin (x)

f (x, y) = - 8 x^{3} y + 2 x y^{2} - 5 x^{2} y^{5} + 12 x

f (x) = 9 x^{4} - 4 x^{3}

f (x, y) = 4 x^{2} y - 2 x - y^{2}

f (x) = \frac{x ^{5} - 5 x}{5}

What is the extreme f(x)=10+x^3-(9x^2)/2 ?
The extreme f(x)=10+x^3-(9x^2)/2 is Maximum(0,10),Minimum(3,-7/2)