What is the extreme f(x)=x^3-12x^2+45x+7 ?

The extreme f(x)=x^3-12x^2+45x+7 is Maximum(3,61),Minimum(5,57)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3-12x^2+45x+7

extreme points

f (x) = x^{3} - 12 x^{2} + 45 x + 7

Maximum (3, 61), Minimum (5, 57)

Solution steps

f^{'} (x) = 3 x^{2} - 24 x + 45

Find intervals:

Increasing

: - \infty < x < 3,

Decreasing

: 3 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = 3

into

x^{3} - 12 x^{2} + 45 x + 7 : 61

Maximum (3, 61)

Plug

x = 5

into

x^{3} - 12 x^{2} + 45 x + 7 : 57

Minimum (5, 57)

Maximum (3, 61), Minimum (5, 57)

f (x) = x^{7} (x + 4)^{4}, - 10 \leq x \leq 13

y = x^{4} - 8 x^{2} + 5

f (x) = (x - 7) e^{x}

y (x, t) = 3 x + 2 a t (3.4)

f (x) = - 3 (x + 2) e^{4 x}

What is the extreme f(x)=x^3-12x^2+45x+7 ?
The extreme f(x)=x^3-12x^2+45x+7 is Maximum(3,61),Minimum(5,57)