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Popular >

extreme f(x)=sqrt(x^2+64)

Solution

extreme points

f (x) = x^{2} + 64

Solution

Minimum (0, 8)

Solution steps

f^{'} (x) = \frac{x}{x ^{2} + 64}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{2} + 64 : 8

Minimum (0, 8)

Popular Examples

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y = 150 x - 50 x^{2} + 4 x^{3}

extreme f(x)=2x^3+1 extreme points

f (x) = 2 x^{3} + 1

extreme 1/4 x^4-2x^3+3x^2+2 extreme points

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extreme f(x)=x+(16)/x ,0.2<= x<= 16 extreme points

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extreme f(x)=3x^{5/3}-2x^{2/3}extreme points

f (x) = 3 x^{\frac{5}{3}} - 2 x^{\frac{2}{3}}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=sqrt(x^2+64) ?
The extreme f(x)=sqrt(x^2+64) is Minimum(0,8)