What is the extreme f(x,y)=xy-x^3-y^2 ?

The extreme f(x,y)=xy-x^3-y^2 is Saddle(0,0),Maximum(1/6 , 1/12)

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extreme f(x,y)=xy-x^3-y^2

extreme points

f (x, y) = x y - x^{3} - y^{2}

Saddle (0, 0), Maximum (\frac{1}{6}, \frac{1}{12})

Solution steps

Find the critical points:

(0, 0), (\frac{1}{6}, \frac{1}{12})

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = 12 x - 1

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Check critical point

(\frac{1}{6}, \frac{1}{12}) :

Maximum

Saddle (0, 0), Maximum (\frac{1}{6}, \frac{1}{12})

f (x) = x^{3} - \frac{27}{2} x^{2} + 42 x + 1

f (x) = - 2 x 3 - x

f (x) = 1.1 x^{4} - 5.1 x^{2} + 4.07

f (x) = - x^{2} + 4 x - 2

\frac{e ^{x}}{5 + e ^{x}}

What is the extreme f(x,y)=xy-x^3-y^2 ?
The extreme f(x,y)=xy-x^3-y^2 is Saddle(0,0),Maximum(1/6 , 1/12)