What is the extreme f(x,y)=x^6+xy-2y-x+3 ?

The extreme f(x,y)=x^6+xy-2y-x+3 is Saddle(2,-191)

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extreme f(x,y)=x^6+xy-2y-x+3

extreme points

f (x, y) = x^{6} + x y - 2 y - x + 3

Saddle (2, - 191)

Solution steps

Find the critical points:

(2, - 191)

\frac{\partial ^{2} f}{\partial x ^{2}} = 0

D (x, y) = - 1

Check the sign of at each critical point

Check critical point

(2, - 191) :

Saddle

Saddle (2, - 191)

f (x) = 3 cos^{2} (x)

f (x) = 6 x - 7 x^{\frac{6}{7}}

- x^{3}

f (x) = x (ln (x))^{2}

f (x) = x^{3} + 3 x^{2} + 4

What is the extreme f(x,y)=x^6+xy-2y-x+3 ?
The extreme f(x,y)=x^6+xy-2y-x+3 is Saddle(2,-191)