What is the extreme f(x)=-x^3+12x-14 ?

The extreme f(x)=-x^3+12x-14 is Minimum(-2,-30),Maximum(2,2)

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extreme f(x)=-x^3+12x-14

extreme points

f (x) = - x^{3} + 12 x - 14

Minimum (- 2, - 30), Maximum (2, 2)

Solution steps

f^{'} (x) = - 3 x^{2} + 12

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = - 2

into

- x^{3} + 12 x - 14 : - 30

Minimum (- 2, - 30)

Plug

x = 2

into

- x^{3} + 12 x - 14 : 2

Maximum (2, 2)

Minimum (- 2, - 30), Maximum (2, 2)

f (x) = 200 - 8 y = 0

f (x) = (x - 5) ln (x - 5)

f (x) = x^{2} + 5 x + 6

f (x) = 2 sec (x) - tan (x)

f (x) = \frac{x ^{2} - 9 x + 39}{x - 7}

What is the extreme f(x)=-x^3+12x-14 ?
The extreme f(x)=-x^3+12x-14 is Minimum(-2,-30),Maximum(2,2)