What is the extreme f(x)=x^3-27x+58 ?

The extreme f(x)=x^3-27x+58 is Maximum(-3,112),Minimum(3,4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3-27x+58

extreme points

f (x) = x^{3} - 27 x + 58

Maximum (- 3, 112), Minimum (3, 4)

Solution steps

f^{'} (x) = 3 x^{2} - 27

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

x^{3} - 27 x + 58 : 112

Maximum (- 3, 112)

Plug

x = 3

into

x^{3} - 27 x + 58 : 4

Minimum (3, 4)

Maximum (- 3, 112), Minimum (3, 4)

f (x) = \frac{x}{x ^{2} - 36}

f (x, y) = 32 y^{2} + x^{2} - x^{2} y

f (x) = x^{4} - 8 x^{3} + 22 x^{2} - 24 x

f (x) = - \frac{5 x ^{3}}{3} + 10 x^{2} + 25 x

f (x) = 8 - 3 x - 6 x^{2}

What is the extreme f(x)=x^3-27x+58 ?
The extreme f(x)=x^3-27x+58 is Maximum(-3,112),Minimum(3,4)