en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^2+8x+13

Solution

extreme points

f (x) = x^{2} + 8 x + 13

Solution

Minimum (- 4, - 3)

Solution steps

f^{'} (x) = 2 x + 8

Find intervals:

Decreasing

: - \infty < x < - 4,

Increasing

: - 4 < x < \infty

Plug

x = - 4

into

x^{2} + 8 x + 13 : - 3

Minimum (- 4, - 3)

Popular Examples

extreme f(x)=15x^4-4x^3 extreme points

f (x) = 15 x^{4} - 4 x^{3}

extreme f(x)=x^3-5/2 x^2-2x extreme points

f (x) = x^{3} - \frac{5}{2} x^{2} - 2 x

extreme f(x)=2+x-x^2 extreme points

f (x) = 2 + x - x^{2}

extreme f(x,y)=x^3-12x-y^2-8y+18 extreme points

f (x, y) = x^{3} - 12 x - y^{2} - 8 y + 18

extreme f(x)=45x+y extreme points

f (x) = 45 x + y

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+8x+13 ?
The extreme f(x)=x^2+8x+13 is Minimum(-4,-3)