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Popular >

midpoint (-7,2),(3,-3)

Solution

midpoint

(- 7, 2), (3, - 3)

Solution

(- 2, - \frac{1}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 7, 2), (x_{2}, y_{2}) = (3, - 3)

= (\frac{3 - 7}{2}, \frac{- 3 + 2}{2})

Refine

= (- 2, - \frac{1}{2})

Popular Examples

critical f(x)=(x^2)/(x^2-4)critical points

f (x) = \frac{x ^{2}}{x ^{2} - 4}

range of f(x)=2x^2-7x-4 range

f (x) = 2 x^{2} - 7 x - 4

critical f(x)=-x^3+2x^2+2 critical points

f (x) = - x^{3} + 2 x^{2} + 2

domain of f(x)= 2/((x^2+4))domain

f (x) = \frac{2}{( x ^{2} + 4 )}

distance (-4,-3),(2,5)distance

(- 4, - 3), (2, 5)

Frequently Asked Questions (FAQ)

What is the midpoint (-7,2),(3,-3) ?
The midpoint (-7,2),(3,-3) is (-2,-1/2)