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Popular >

extreme f(x)=2x^2-10x+5

Solution

extreme points

f (x) = 2 x^{2} - 10 x + 5

Solution

Minimum (\frac{5}{2}, - \frac{15}{2})

Solution steps

f^{'} (x) = 4 x - 10

Find intervals:

Decreasing

: - \infty < x < \frac{5}{2},

Increasing

: \frac{5}{2} < x < \infty

Plug

x = \frac{5}{2}

into

2 x^{2} - 10 x + 5 : - \frac{15}{2}

Minimum (\frac{5}{2}, - \frac{15}{2})

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2-10x+5 ?
The extreme f(x)=2x^2-10x+5 is Minimum(5/2 ,-15/2)