What is the extreme f(x)=x^4-18x^2+4 ?

The extreme f(x)=x^4-18x^2+4 is Minimum(-3,-77),Maximum(0,4),Minimum(3,-77)

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extreme f(x)=x^4-18x^2+4

extreme points

f (x) = x^{4} - 18 x^{2} + 4

Minimum (- 3, - 77), Maximum (0, 4), Minimum (3, - 77)

Solution steps

f^{'} (x) = 4 x^{3} - 36 x

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: - 3 < x < 0,

Decreasing

: 0 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

x^{4} - 18 x^{2} + 4 : - 77

Minimum (- 3, - 77)

Plug

x = 0

into

x^{4} - 18 x^{2} + 4 : 4

Maximum (0, 4)

Plug

x = 3

into

x^{4} - 18 x^{2} + 4 : - 77

Minimum (3, - 77)

Minimum (- 3, - 77), Maximum (0, 4), Minimum (3, - 77)

f (x) = x^{2} + 10 x + 9

y = 7 x - 7 z - 9

y, y < 3 x - 4

f (x) = 2 - x^{4} + 2 x^{2} - y^{2}

f (x) = \frac{ln ( 2 x )}{x}

What is the extreme f(x)=x^4-18x^2+4 ?
The extreme f(x)=x^4-18x^2+4 is Minimum(-3,-77),Maximum(0,4),Minimum(3,-77)