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Popular >

extreme f(x)=x^2+5x

Solution

extreme points

f (x) = x^{2} + 5 x

Solution

Minimum (- \frac{5}{2}, - \frac{25}{4})

Solution steps

f^{'} (x) = 2 x + 5

Find intervals:

Decreasing

: - \infty < x < - \frac{5}{2},

Increasing

: - \frac{5}{2} < x < \infty

Plug

x = - \frac{5}{2}

into

x^{2} + 5 x : - \frac{25}{4}

Minimum (- \frac{5}{2}, - \frac{25}{4})

Graph

Popular Examples

extreme f(x)=x^5-5x^3 extreme points

f (x) = x^{5} - 5 x^{3}

extreme P(x,y)=x^3(x+y)+5xy(x+y)extreme points

P (x, y) = x^{3} (x + y) + 5 x y (x + y)

extreme f(x)=-x^3+27x-61 extreme points

f (x) = - x^{3} + 27 x - 61

extreme f(x)=2sec(x),-pi/3 <= x<= pi/3 extreme points

f (x) = 2 sec (x), - \frac{π}{3} \leq x \leq \frac{π}{3}

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f (x) = - 3 x^{3} + 3 x^{2} - x - 1

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+5x ?
The extreme f(x)=x^2+5x is Minimum(-5/2 ,-25/4)