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Popular Functions >

extreme f(x)=(8-4x)^8

Solution

extreme points

f (x) = (8 - 4 x)^{8}

Solution

Minimum (2, 0)

Solution steps

f^{'} (x) = - 32 (8 - 4 x)^{7}

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

(8 - 4 x)^{8} : 0

Minimum (2, 0)

Graph

Popular Examples

extreme f(x)=2x^2-8x^4 extreme points

f (x) = 2 x^{2} - 8 x^{4}

extreme f(x)=-x^{2/3}(x-3),-3<= x<= 3 extreme points

f (x) = - x^{\frac{2}{3}} (x - 3), - 3 \leq x \leq 3

extreme x^{3/5}extreme points

x^{\frac{3}{5}}

extreme f(x)=(8.7x+0.2)/(x^2-4.5x+7.5)extreme points

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extreme f(t)=(e^t)/(t^2+1),(0,3)extreme points

f (t) = \frac{e ^{t}}{t ^{2} + 1}, (0, 3)

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(8-4x)^8 ?
The extreme f(x)=(8-4x)^8 is Minimum(2,0)