What is the extreme f(x)=x^4-98x^2+4 ?

The extreme f(x)=x^4-98x^2+4 is Minimum(-7,-2397),Maximum(0,4),Minimum(7,-2397)

extreme f(x)=x^4-98x^2+4

extreme points

f (x) = x^{4} - 98 x^{2} + 4

Minimum (- 7, - 2397), Maximum (0, 4), Minimum (7, - 2397)

Solution steps

f^{'} (x) = 4 x^{3} - 196 x

Find intervals:

Decreasing

: - \infty < x < - 7,

Increasing

: - 7 < x < 0,

Decreasing

: 0 < x < 7,

Increasing

: 7 < x < \infty

Plug

x = - 7

into

x^{4} - 98 x^{2} + 4 : - 2397

Minimum (- 7, - 2397)

Plug

x = 0

into

x^{4} - 98 x^{2} + 4 : 4

Maximum (0, 4)

Plug

x = 7

into

x^{4} - 98 x^{2} + 4 : - 2397

Minimum (7, - 2397)

Minimum (- 7, - 2397), Maximum (0, 4), Minimum (7, - 2397)

(x + 3)^{2} (x^{3} - x^{2})

f (x) = (x + 2)^{3} - 5

f (x) = (x - 2) e^{x}

f (x) = 6 x^{\frac{2}{3}}

2 x^{3} + 3 x^{2} - 72 x

What is the extreme f(x)=x^4-98x^2+4 ?
The extreme f(x)=x^4-98x^2+4 is Minimum(-7,-2397),Maximum(0,4),Minimum(7,-2397)