en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^{2/3}-7

Solution

extreme points

f (x) = x^{\frac{2}{3}} - 7

Solution

Minimum (0, - 7)

Solution steps

f^{'} (x) = \frac{2}{3 x ^{\frac{1}{3}}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{\frac{2}{3}} - 7 : - 7

Minimum (0, - 7)

Graph

Popular Examples

extreme f(x)=x^4+2x^3-2x+5 extreme points

f (x) = x^{4} + 2 x^{3} - 2 x + 5

extreme f(x,y)=2x^2+4y^2+1/2 extreme points

f (x, y) = 2 x^{2} + 4 y^{2} + \frac{1}{2}

extreme f(x)=(x^2+2)/(x+1)extreme points

f (x) = \frac{x ^{2} + 2}{x + 1}

extreme f(x)=2x-11ln(8x),2<= x<= 9 extreme points

f (x) = 2 x - 11 ln (8 x), 2 \leq x \leq 9

extreme f(x)=3x^{2/3},-1<= x<= 1 extreme points

f (x) = 3 x^{\frac{2}{3}}, - 1 \leq x \leq 1

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^{2/3}-7 ?
The extreme f(x)=x^{2/3}-7 is Minimum(0,-7)