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Popular >

extreme f(x)=x^3+5

Solution

extreme points

f (x) = x^{3} + 5

Solution

Saddle (0, 5)

Solution steps

f^{'} (x) = 3 x^{2}

Find intervals:

Increasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{3} + 5 : 5

Saddle (0, 5)

Graph

Popular Examples

extreme f(x)=2x(x+4)^3 extreme points

f (x) = 2 x (x + 4)^{3}

extreme f(x)=x^3-9x^2+8 extreme points

f (x) = x^{3} - 9 x^{2} + 8

extreme f(x)=(-6)/(x-7)extreme points

f (x) = \frac{- 6}{x - 7}

extreme f(x)=xln(x/5)extreme points

f (x) = x ln (\frac{x}{5})

extreme f(x)=x^3-2x^2-4x+12 extreme points

f (x) = x^{3} - 2 x^{2} - 4 x + 12

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^3+5 ?
The extreme f(x)=x^3+5 is Saddle(0,5)