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Popular >

extreme f(x)= 2/(x^2+3)

Solution

extreme points

f (x) = \frac{2}{x ^{2} + 3}

Solution

Maximum (0, \frac{2}{3})

Solution steps

f^{'} (x) = - \frac{4 x}{( x ^{2} + 3 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = 0

into

\frac{2}{x ^{2} + 3} : \frac{2}{3}

Maximum (0, \frac{2}{3})

Graph

Popular Examples

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f (x) = x^{2} (x^{2} - 1)

extreme f(x)= x/(x^2-1),(0,5)extreme points

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extreme f(x,y)=x^2+2y^2+xy-5x-6y extreme points

f (x, y) = x^{2} + 2 y^{2} + x y - 5 x - 6 y

extreme (-x^2+1)/((x^2+1)^2)extreme points

\frac{- x ^{2} + 1}{( x ^{2} + 1 ) ^{2}}

extreme f(x)=(x^2-5)/(x+3)extreme points

f (x) = \frac{x ^{2} - 5}{x + 3}

Frequently Asked Questions (FAQ)

What is the extreme f(x)= 2/(x^2+3) ?
The extreme f(x)= 2/(x^2+3) is Maximum(0, 2/3)