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Popular >

extreme f(x)=x^4+32x

Solution

extreme points

f (x) = x^{4} + 32 x

Solution

Minimum (- 2, - 48)

Solution steps

f^{'} (x) = 4 x^{3} + 32

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 2

into

x^{4} + 32 x : - 48

Minimum (- 2, - 48)

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^4+32x ?
The extreme f(x)=x^4+32x is Minimum(-2,-48)