What is the extreme f(x)= 1/4 x^4-2x^3+1 ?

The extreme f(x)= 1/4 x^4-2x^3+1 is Saddle(0,1),Minimum(6,-107)

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extreme f(x)= 1/4 x^4-2x^3+1

extreme points

f (x) = \frac{1}{4} x^{4} - 2 x^{3} + 1

Saddle (0, 1), Minimum (6, - 107)

Solution steps

f^{'} (x) = x^{3} - 6 x^{2}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 0

into

\frac{1}{4} x^{4} - 2 x^{3} + 1 : 1

Saddle (0, 1)

Plug

x = 6

into

\frac{1}{4} x^{4} - 2 x^{3} + 1 : - 107

Minimum (6, - 107)

Saddle (0, 1), Minimum (6, - 107)

y = \frac{x}{x ^{2} + 4}

y = x (x - 1)^{5}

f (x) = x^{3} + 6 x^{2} - 6

f (x, y) = x y + x^{2} + y^{2} - x + y + 17

f (x) = 2 x^{3} - 3 x^{2} - 12 x + 1, - 4 \leq x \leq 5

What is the extreme f(x)= 1/4 x^4-2x^3+1 ?
The extreme f(x)= 1/4 x^4-2x^3+1 is Saddle(0,1),Minimum(6,-107)