What is the extreme f(x)=6+9x^2-6x^3 ?

The extreme f(x)=6+9x^2-6x^3 is Minimum(0,6),Maximum(1,9)

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extreme f(x)=6+9x^2-6x^3

extreme points

f (x) = 6 + 9 x^{2} - 6 x^{3}

Minimum (0, 6), Maximum (1, 9)

Solution steps

f^{'} (x) = - 18 x^{2} + 18 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = 0

into

6 + 9 x^{2} - 6 x^{3} : 6

Minimum (0, 6)

Plug

x = 1

into

6 + 9 x^{2} - 6 x^{3} : 9

Maximum (1, 9)

Minimum (0, 6), Maximum (1, 9)

f (x) = 14 x + 17 x^{\frac{14}{17}}

f (x, y) = 2 x y - 6 y^{2} + x^{2} y - 3 y + 7

f (x) = 2 x^{4} - x^{2} + 5

f (x) = 2 x^{2} + x + 2

y = 6 x^{4} + 8 x^{3}

What is the extreme f(x)=6+9x^2-6x^3 ?
The extreme f(x)=6+9x^2-6x^3 is Minimum(0,6),Maximum(1,9)