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Popular >

extreme f(x)=1+2x-3x^2

Solution

extreme points

f (x) = 1 + 2 x - 3 x^{2}

Solution

Maximum (\frac{1}{3}, \frac{4}{3})

Solution steps

f^{'} (x) = - 6 x + 2

Find intervals:

Increasing

: - \infty < x < \frac{1}{3},

Decreasing

: \frac{1}{3} < x < \infty

Plug

x = \frac{1}{3}

into

1 + 2 x - 3 x^{2} : \frac{4}{3}

Maximum (\frac{1}{3}, \frac{4}{3})

Graph

Popular Examples

extreme f(5/4 , 1/4)=2xy-x^2-5y^2+2x+1 extreme points

f (\frac{5}{4}, \frac{1}{4}) = 2 x y - x^{2} - 5 y^{2} + 2 x + 1

extreme f(x)=3+x^2+xy+y^2 extreme points

f (x) = 3 + x^{2} + x y + y^{2}

extreme f(x)=2x+2y extreme points

f (x) = 2 x + 2 y

extreme f(x)=(ln(x))/(2x)extreme points

f (x) = \frac{ln ( x )}{2 x}

extreme f(x,y)=23-2x^3-y^2-6xy extreme points

f (x, y) = 23 - 2 x^{3} - y^{2} - 6 x y

Frequently Asked Questions (FAQ)

What is the extreme f(x)=1+2x-3x^2 ?
The extreme f(x)=1+2x-3x^2 is Maximum(1/3 , 4/3)