What is the extreme f(x)=(2e^{3x})/(-2x-5) ?

The extreme f(x)=(2e^{3x})/(-2x-5) is Maximum(-13/6 ,-3/(e^{13/2)})

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=(2e^{3x})/(-2x-5)

extreme points

f (x) = \frac{2 e ^{3 x}}{- 2 x - 5}

Maximum (- \frac{13}{6}, - \frac{3}{e ^{\frac{13}{2}}})

Solution steps

f^{'} (x) = \frac{2 ( - 6 e ^{3 x} x - 13 e ^{3 x} )}{( - 2 x - 5 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - \frac{5}{2},

Increasing

: - \frac{5}{2} < x < - \frac{13}{6},

Decreasing

: - \frac{13}{6} < x < \infty

Plug

x = - \frac{13}{6}

into

\frac{2 e ^{3 x}}{- 2 x - 5} : - \frac{3}{e ^{\frac{13}{2}}}

Maximum (- \frac{13}{6}, - \frac{3}{e ^{\frac{13}{2}}})

f (x) = x^{4} + x^{2} + 3

f (x) = x^{4} - 5 x^{3} - 15 x^{2}

f (x, y) = x + 2 y

5 sin^{2} (x)

f (x) = - x^{2} + 3 x + 5

What is the extreme f(x)=(2e^{3x})/(-2x-5) ?
The extreme f(x)=(2e^{3x})/(-2x-5) is Maximum(-13/6 ,-3/(e^{13/2)})