What is the extreme A-2/(X-2)+1/((X-2)^2) ?

The extreme A-2/(X-2)+1/((X-2)^2) is Minimum(3,A-1)

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extreme A-2/(X-2)+1/((X-2)^2)

extreme points

A - \frac{2}{X - 2} + \frac{1}{( X - 2 ) ^{2}}

Minimum (3, A - 1)

Solution steps

f^{'} (X) = - \frac{2 ( - X + 3 )}{( X - 2 ) ^{3}}

Find intervals:

Increasing

: - \infty < X < 2,

Decreasing

: 2 < X < 3,

Increasing

: 3 < X < \infty

Plug

X = 3

into

A - \frac{2}{X - 2} + \frac{1}{( X - 2 ) ^{2}} : A - 1

Minimum (3, A - 1)

f (x, y) = 2 x^{2} + 3 y^{2} - 4 x + 12 y + 13

f (x) = x^{3} - x^{2} - x + 7

sin (x) - cos (x)

y = x + e^{- 4 x}

f (x) = 3 (x^{2} - 1)^{2}

What is the extreme A-2/(X-2)+1/((X-2)^2) ?
The extreme A-2/(X-2)+1/((X-2)^2) is Minimum(3,A-1)